Asked by Em
At sea level, a hydrogen molecule in the air has an average kinetic energy of 5.53×10-21 J. Its mass is 3.32×10-27 kg. The hydrogen molecule shoots straight up without colliding with the molecules in the air. (Assume that you can use g = 9.81 m/s2; although we’ll see in Chapter 12 that this assumption may not be justified for this situation.)
I found the initial speed to be: 1825.2 m/s
but now i need to find How high would it rise?
in order to do that i would use the equation: vf^2=vo^2+2a(x-xo)
I have everything to plug in to find the height EXCEPT for the final velocity, what is the final velocity? or how would i find it?
Thank You so much :)
I found the initial speed to be: 1825.2 m/s
but now i need to find How high would it rise?
in order to do that i would use the equation: vf^2=vo^2+2a(x-xo)
I have everything to plug in to find the height EXCEPT for the final velocity, what is the final velocity? or how would i find it?
Thank You so much :)
Answers
Answered by
bobpursley
final velocity at max height is zero.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.