Asked by Anonymous

A boy kicks a rock off a cliff with a speed of 19.4 m/s at an angle of 52.5° above the horizontal. The rock hits the ground 5.41 s after it was kicked.

a) How high is the cliff? (I found the height to be 60.3 m)

b) What is the speed of the rock right before it hits the ground?

c) What is the maximum height of the rock measured from the top of the cliff?
Answered by ANON
BUMP!
Answered by tom
30
21
2
Answered by yara
(b) first
V2x = Vox = ____ m/s i
Vox = 19.4cos52.5

second
Y2 = height of cliff (negative)

You want to find V2y
V2y^2 = Voy^2 + 2ay[Y2-Yo]
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