a rock is thrown of a cliff with an horizontal velocity of 55.0 m/sec. it takes the rock 7.0 sec to hit the ground

Question

a) what is the height of the cliff.
b)how far from the foot of the cliff does the rock hit the ground.
c) what is the vertical component of velocity with which its hits the ground.
d) what is the vertical component of velocity with which hits the ground.

Answer 1

a) There is an equation for distance fallen vs time that you should know.
y = (g/2) t^2
Use it to solve for t.

b) 55.0 t

c) g*t

d) same question as c). Same answer. You probably typed part of the question wrong.