Asked by stacy

A rock is thrown from a cliff top at 18m/s, 25 degrees above the horizontal. It lands on the beach 4.2 seconds later.

a) What is the height of the cliff?
b) Hor far from the base of the cliff did the rock land?

Answers

Answered by bobpursley
vertical veloctiy: 18sin25

Hf=hi+viv*t-1/2 g t^2

hf=0, hi=unknown,viv=18sin25, t=4.2 solve for hi.

horizontal distance? 18cos25*4.2
Answered by stacy
great, thank you so much!
Answered by Anonymous
56
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions