Asked by stacy
A rock is thrown from a cliff top at 18m/s, 25 degrees above the horizontal. It lands on the beach 4.2 seconds later.
a) What is the height of the cliff?
b) Hor far from the base of the cliff did the rock land?
a) What is the height of the cliff?
b) Hor far from the base of the cliff did the rock land?
Answers
Answered by
bobpursley
vertical veloctiy: 18sin25
Hf=hi+viv*t-1/2 g t^2
hf=0, hi=unknown,viv=18sin25, t=4.2 solve for hi.
horizontal distance? 18cos25*4.2
Hf=hi+viv*t-1/2 g t^2
hf=0, hi=unknown,viv=18sin25, t=4.2 solve for hi.
horizontal distance? 18cos25*4.2
Answered by
stacy
great, thank you so much!
Answered by
Anonymous
56
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