Asked by Priscilla
A soccer player kicks a rock with an initial velocity of 0.50 m/s from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released?
Vi = 0.50 m;s
h = 4 m
t = 0.70 s
Vi = 0.50 m;s
h = 4 m
t = 0.70 s
Answers
Answered by
bobpursley
You know the intial horizontal velocity.
the final vertical velocity is..
vfv=gt find that, then add it to the horizontal velocity as a VECTOR.
vf=sqrt(vfv^2 + Vihorz^2)
the final vertical velocity is..
vfv=gt find that, then add it to the horizontal velocity as a VECTOR.
vf=sqrt(vfv^2 + Vihorz^2)
Answered by
Anonymous
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the horizontal velocity component of the ball to the nearest tenth of a m/s?
Answered by
Anonymous
A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. How long was the ball in the air? Round the answer to the nearest tenth of a second.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.