A soccer player kicks a rock with an initial velocity of 0.50 m/s from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released?

Vi = 0.50 m;s
h = 4 m
t = 0.70 s

3 answers

You know the intial horizontal velocity.
the final vertical velocity is..

vfv=gt find that, then add it to the horizontal velocity as a VECTOR.

vf=sqrt(vfv^2 + Vihorz^2)
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