Asked by dave

An electron in the n = 5 excited state of a hydrogen atom emits a photon of 1281 nm light. To what energy level does the electron move?

Any ideas on an equation for this? Is it some kind of backward version of Rydburg Eq?
Answered by bobpursley
conver nm to energy.

E=h*c/lambda

then, having E, find the n.
Answered by dave
h*c/lambda
would this be planck's constant times speed of light / wavelength?
Answered by DrBob222
Yes. Another way to do it
(1/wavelength) = R(1/n^2 - 1/5^2)
where R is the Rydberg constant. Solve for n.
Answered by Emily
How many photons of light are emitted when the electrons in 10 hydrogen atoms drop from energy level 5 to 3?
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