Asked by myke
a diver running at 1,8 m.s dives out horizontally from the edge of a high vertical cliff. He hits the water 2 seconds later. How high was the cliff?
Answers
Answered by
bobpursley
so it took 2 seconds to fall.
hf=hi-9.8/2 * t^2 hf=0, solve for hi.
YOu really ought to memorize these equations. Hundreds of millions before you have done so.
hf=hi-9.8/2 * t^2 hf=0, solve for hi.
YOu really ought to memorize these equations. Hundreds of millions before you have done so.
Answered by
Anonymous
first you want to
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