Asked by Katie
A diver running 2.4 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below. How high was the cliff?
Answers
Answered by
MathMate
The horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.
What is important is the initial velocity is horizontal, so the vertical component, u, is zero.
vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*2.6²
=?
What is important is the initial velocity is horizontal, so the vertical component, u, is zero.
vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*2.6²
=?
Answered by
Anonymous
0.72
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