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Asked by Mitch

Perimeter = 216 and the length is (2X)+3 more than the width. How do I solve for X and what is the rectangle length. I am really stuck!
14 years ago

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Answered by PsyDAG
W = X
L = 2X + 3

216 = 2X + 2(2X+3)

Solve for X, then 2X + 3.
14 years ago
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Perimeter = 216 and the length is (2X)+3 more than the width. How do I solve for X and what is the rectangle length. I am really stuck!

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