Asked by Deby
Perimeter is 290ft and length is 43ft longer than the width. What are the dimensions of the room
Answers
Answered by
Bosnian
If the room have rectangle form then :
L = W + 23
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( W + W + 23 )
P = 2 ( 2 W + 23 )
P = 4 W + 46
290 = 4 W + 46 Subtract 46 to both sides
290 - 46 = 4 W + 46 - 46
244 = 4 W Divide both sides by 4
244 / 4 = 4 W / 4
61 = W
W = 61 ft
L = W + 23
L = 61 + 23 = 84 ft
Proof :
P = 2 ( W + L ) = 2 ( 61 + 84 ) = 2 * 145 = 290 ft
L = W + 23
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( W + W + 23 )
P = 2 ( 2 W + 23 )
P = 4 W + 46
290 = 4 W + 46 Subtract 46 to both sides
290 - 46 = 4 W + 46 - 46
244 = 4 W Divide both sides by 4
244 / 4 = 4 W / 4
61 = W
W = 61 ft
L = W + 23
L = 61 + 23 = 84 ft
Proof :
P = 2 ( W + L ) = 2 ( 61 + 84 ) = 2 * 145 = 290 ft
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