Asked by Deby

Perimeter is 290ft and length is 43ft longer than the width. What are the dimensions of the room

Answers

Answered by Bosnian
If the room have rectangle form then :

L = W + 23


P = 2 W + 2 L

P = 2 ( W + L )

P = 2 ( W + W + 23 )

P = 2 ( 2 W + 23 )

P = 4 W + 46

290 = 4 W + 46 Subtract 46 to both sides

290 - 46 = 4 W + 46 - 46

244 = 4 W Divide both sides by 4

244 / 4 = 4 W / 4

61 = W

W = 61 ft


L = W + 23

L = 61 + 23 = 84 ft


Proof :

P = 2 ( W + L ) = 2 ( 61 + 84 ) = 2 * 145 = 290 ft

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