Asked by Deby
                Perimeter is 290ft and length is 43ft longer than the width. What are the dimensions of the room
            
            
        Answers
                    Answered by
            Bosnian
            
    If the room have rectangle form then :
L = W + 23
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( W + W + 23 )
P = 2 ( 2 W + 23 )
P = 4 W + 46
290 = 4 W + 46 Subtract 46 to both sides
290 - 46 = 4 W + 46 - 46
244 = 4 W Divide both sides by 4
244 / 4 = 4 W / 4
61 = W
W = 61 ft
L = W + 23
L = 61 + 23 = 84 ft
Proof :
P = 2 ( W + L ) = 2 ( 61 + 84 ) = 2 * 145 = 290 ft
    
L = W + 23
P = 2 W + 2 L
P = 2 ( W + L )
P = 2 ( W + W + 23 )
P = 2 ( 2 W + 23 )
P = 4 W + 46
290 = 4 W + 46 Subtract 46 to both sides
290 - 46 = 4 W + 46 - 46
244 = 4 W Divide both sides by 4
244 / 4 = 4 W / 4
61 = W
W = 61 ft
L = W + 23
L = 61 + 23 = 84 ft
Proof :
P = 2 ( W + L ) = 2 ( 61 + 84 ) = 2 * 145 = 290 ft
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