Asked by Anonymous
a plane is one mile above sea level when it begins to climb at a constant angle of 3 degrees for the next 60 ground miles. about how far above sea level is the plane after its climb
Answers
Answered by
helper
You need to draw right triangle ABC.
Angle A (vertex angle) = 3 deg
side b (base) = 60 mi
side c = hypotenuse
side a (distance of climb) = unknown
tan A = op/hyp = a/b = a/60
tan 3 = a/60
0.0524 = a/60
60(0.0524) = a
3.144 mi = a
So the plane climbed 3.144 miles
To find how far above sea level after the climb,
1 mile + 3.144 miles = 4.144 miles above sea level
Angle A (vertex angle) = 3 deg
side b (base) = 60 mi
side c = hypotenuse
side a (distance of climb) = unknown
tan A = op/hyp = a/b = a/60
tan 3 = a/60
0.0524 = a/60
60(0.0524) = a
3.144 mi = a
So the plane climbed 3.144 miles
To find how far above sea level after the climb,
1 mile + 3.144 miles = 4.144 miles above sea level
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