Asked by gisela
A plane makes an 900-mile flight in
3 1/3 hours against a strong head wind, but returns in 50 minutes less with the wind. What is the plane's speed without the wind?
3 1/3 hours against a strong head wind, but returns in 50 minutes less with the wind. What is the plane's speed without the wind?
Answers
Answered by
Henry
Vp-Vw=900/(10/3) = 900 * 3/10 = 270 mi/h
Vp+Vw=900/(50/60)=900 * 60/50=1080 mi/h
Vp - Vw = 270
Vp + Vw = 1080
Sum: 2Vp = 1350
Vp = 675 mi/h. = Velocity of plane without the wind.
Vp+Vw=900/(50/60)=900 * 60/50=1080 mi/h
Vp - Vw = 270
Vp + Vw = 1080
Sum: 2Vp = 1350
Vp = 675 mi/h. = Velocity of plane without the wind.
Answered by
Henry
Correction:
T = 10/3-6/5 = 50/15 - 18/15 = 32/15 =
2.1333 h
Vp+Vw = 900/2.1333 = 421.875 mi/h
Vp = (270+421.875)/2 = 346 mi/h = Velocity of the plane without wind.
T = 10/3-6/5 = 50/15 - 18/15 = 32/15 =
2.1333 h
Vp+Vw = 900/2.1333 = 421.875 mi/h
Vp = (270+421.875)/2 = 346 mi/h = Velocity of the plane without wind.
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