Question
Two blocks are arranged as shown. The pulley can be considered to be massless, and friction is negligible. M1 is four times more massive than M2.
M1--->0(Pulley)
V
V (down direction)
V
M2
If the system is released from rest, how far will M1 travel in 0.523 s?
M1--->0(Pulley)
V
V (down direction)
V
M2
If the system is released from rest, how far will M1 travel in 0.523 s?
Answers
Megan
M2 is supposed to be hanging down from the pulley
bobpursley
The pulling force is M2*g
The moving mass is (M1+M2)
F=ma
M2*g=(M1+M2)a
solve for a
d=1/2 a t^2
The moving mass is (M1+M2)
F=ma
M2*g=(M1+M2)a
solve for a
d=1/2 a t^2