Asked by CR
Two blocks are arranged at the ends of a massless string as shown in the figure. The system starts from rest. When the 3.21 kg mass has fallen through 0.4 m, its downward speed is 1.27 m/s. The acceleration of gravity is 9.8 m/s2 .
3.21 kg (box hanging from table)
4.96 kg (box on table)
ì
a
What is the frictional force between the 4.96 kg mass and the table?
Answer in units of N.
3.21 kg (box hanging from table)
4.96 kg (box on table)
ì
a
What is the frictional force between the 4.96 kg mass and the table?
Answer in units of N.
Answers
Answered by
Matt
Use the kinematic equation v^2=u^2+2ax
When you find the acceleration multiply it by the mass of the block on the table
When you find the acceleration multiply it by the mass of the block on the table
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