a) Solve (1/2)k X^2 = M g H for the maximum height, H
b) Solve (1/2) k X^2 = (1/2) M V^2
for the initial velocity, V
X is the initial compression, which I assume is in meters. (You should have said what the dimensions are)
k is the spring constant and M is the mass.
a man is on the ground level on a compressed spring. the man has a mass of 60kg and the spring is compressed 0.5 and has a spring constant of 500n-m.
a)what is the maximum height will the man achieve and the spring decompresses?
B)find the velocity right after he leaves the spring.
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