Asked by Ararsa
The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?
Answers
Answered by
Steve
solve for t in
-16t^3 + 100t = 72
-16t^3 + 100t - 72 = 0
-4(t-2)(4t^2+8t-9) = 0
...
-16t^3 + 100t = 72
-16t^3 + 100t - 72 = 0
-4(t-2)(4t^2+8t-9) = 0
...
Answered by
Tamitat
Write the full formula
Answered by
Sosina ..10b mcs..
How can l get the all calculation from your...
Answered by
Sosina ..10b mcs..
አገኘሁት አመሰግናለሁ (steve) በሰጠከኝ ፍንጭ.......በብዙ መሞከር egzact ውጤቱን ባነመገኝ እንኳ ብዙ እውቀት እንጨምርበተመለን..so we...
Answered by
fkk
How get fill answer?
Answered by
Adisu Tamrie
Math Nv
Answered by
Daniel aschalew
Di mar
Answered by
Biniam
I need answare in this qesution
Answered by
Neway
The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?
Answered by
Gelatia
thanks your hint
Answered by
Anna
Ere bedenb rejim formual plz?
Answered by
Girma
-16t^3+100t=72
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0
Answered by
chala
answer with explaniation
Answered by
Magarsaa Abraahim
The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?
Answered by
robel tesfaye
-16t^3+100t=72
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0 then divide both sides by -4
(t-2)(4t^2+8t-9)=0
t=2or 👆=0 and since the answer of the quadratic equation is irrational number the answer is just 2.
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0 then divide both sides by -4
(t-2)(4t^2+8t-9)=0
t=2or 👆=0 and since the answer of the quadratic equation is irrational number the answer is just 2.
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