Asked by Ararsa

The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?

Answers

Answered by Steve
solve for t in
-16t^3 + 100t = 72
-16t^3 + 100t - 72 = 0
-4(t-2)(4t^2+8t-9) = 0
...
Answered by Tamitat
Write the full formula
Answered by Sosina ..10b mcs..
How can l get the all calculation from your...
Answered by Sosina ..10b mcs..
አገኘሁት አመሰግናለሁ (steve) በሰጠከኝ ፍንጭ.......በብዙ መሞከር egzact ውጤቱን ባነመገኝ እንኳ ብዙ እውቀት እንጨምርበተመለን..so we...
Answered by fkk
How get fill answer?

Answered by Adisu Tamrie
Math Nv
Answered by Daniel aschalew
Di mar
Answered by Biniam
I need answare in this qesution
Answered by Neway

The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?

Answered by Gelatia
thanks your hint
Answered by Anna
Ere bedenb rejim formual plz?
Answered by Girma
-16t^3+100t=72
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0
Answered by chala
answer with explaniation
Answered by Magarsaa Abraahim
The height above ground level in metres of a missile launch vertically, is given by h(t)=-16t³+100t at what time is the missile 72m above?

Answered by robel tesfaye
-16t^3+100t=72
-16t^3+100t_72=t
t=_4(t_2)(4t^2+8t_9)=0 then divide both sides by -4
(t-2)(4t^2+8t-9)=0
t=2or 👆=0 and since the answer of the quadratic equation is irrational number the answer is just 2.
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