Asked by Yesuf
At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?
Answers
Answered by
Joe
Let s = rate of rotation
Let r = radius of earth = 6,400km
Then solving (s^2) r = g will give the desired rate, from which length of day is inferred.
People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.
Let r = radius of earth = 6,400km
Then solving (s^2) r = g will give the desired rate, from which length of day is inferred.
People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.
Answered by
Yesuf
Thanks
Answered by
Habitu
2 days
Answered by
zelalem
I think curved one is best because as the earth rotate fast we must thrown like cure.
if straight line this not support by gravity
if straight line this not support by gravity
Answered by
Ỳǐşǐşh
I'm not sure
Answered by
Cat
Wow
Answered by
Mohammed
I didn't get it. I need a full explanation. If any one can it please
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