At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?

User Icon for Joe Joe answered
7 years ago

Let s = rate of rotation

Let r = radius of earth = 6,400km
Then solving (s^2) r = g will give the desired rate, from which length of day is inferred.
People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.

User Icon for Yesuf Yesuf answered
7 years ago

Thanks

User Icon for Habitu Habitu answered
5 years ago

2 days

User Icon for zelalem zelalem answered
5 years ago

I think curved one is best because as the earth rotate fast we must thrown like cure.

if straight line this not support by gravity

User Icon for Ỳǐşǐşh Ỳǐşǐşh answered
4 years ago

I'm not sure

User Icon for Cat Cat answered
2 years ago

Wow

User Icon for Mohammed Mohammed answered
2 years ago

I didn't get it. I need a full explanation. If any one can it please