Asked by Anonymous
Dionne is running clockwise. She can run around a circular track in 120 seconds. Basha, running counter-clockwise, meets Dionne every 48 seconds. Sandra runs clockwise and passes Basha every 240 seconds. How often does Sandra meet Dionne in 10 minutes?
Answers
Answered by
drwls
Let Tb be the one-lap time for Basha.
The frequency that Basha and Dionne encounter is
1/48 = 1/120 + 1/Tb, so
1/Tb = 10/480 - 4/480 = 6/480 = 1/80
Tb = 80 seconds
With Sandra and Basha running in opposite directions, and Basha running so fast, they would have to meet more often than every 240 seonds. I believe you made and error stating that Sandra runs clockwise, opposeite to Basha. Check the wording of the problem again.
The frequency that Basha and Dionne encounter is
1/48 = 1/120 + 1/Tb, so
1/Tb = 10/480 - 4/480 = 6/480 = 1/80
Tb = 80 seconds
With Sandra and Basha running in opposite directions, and Basha running so fast, they would have to meet more often than every 240 seonds. I believe you made and error stating that Sandra runs clockwise, opposeite to Basha. Check the wording of the problem again.
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