k = 0.693/t1/2
Substitute k into the equation below.
ln(No/N) = kt
No = 100 mg
You solve for N.
k from above.
t is time from 8:00 am to 1:30 pm but if you substitute half life in minutes, t must be converted to minutes, also.
fluorine-18 half life of 110 min if 100mg was shipped at 8:00 am how many mg are still active at 1;30 pm same day
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