Asked by susan
Fluorine-20 has a half-life of 11.0 s. If a sample initially contains 49.0 μg of this isotope, how much remains after 66.0 s ?
Answers
Answered by
Steve
66s is 6 half-lives, so
49.0 * (1/2)^6 = 0.765 μg
49.0 * (1/2)^6 = 0.765 μg
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