Asked by fatin

What is the half-life of an isotope if it decays to 12.5% of its radioactivity in 18 minutes?
Answered by DrBob222
ln(100/12.5) = k*18
Solve for k, then
k = 0.693/t(sub>1/2</sub>.
Solve for t<sub>1/2</sub>.
Answered by DrBob222
k = 0.693/t<sub>1/2</sub>
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