ok so i got...

the half life of carbon-14 is 5730 years, the relation c+(1/2)^ N/5730 is used to calc. the concentration, c, in parts per trillion remaining n years after death determine the carbon concentration in a 11460 year old bone.
please help :)

User Icon for DrBob222 DrBob222 answered
14 years ago

see above.

User Icon for ghandi ghandi answered
13 years ago

it equals .011460 years

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the carbon concentration in a 11460-year-old bone using the given equation c+ (1/2)^(N/5730), where c represents the concentration in parts per trillion and N represents the number of years after death, you can follow these steps:

Step 1: Substitute the given values into the equation.
c + (1/2)^(N/5730)

Step 2: Determine the value of N by subtracting the age of the bone (11460 years) from the half-life of carbon-14 (5730 years), as the equation uses the number of years after death.
N = 11460 years - 5730 years
N = 5730 years

Step 3: Plug in the value of N (5730) into the equation.
c + (1/2)^(5730/5730)

Step 4: Simplify the equation using the exponent of 5730/5730, which equals 1.
c + (1/2)^1
c + 1/2

Step 5: Separate the two fractions by finding a common denominator.
c/1 + 1/2

Step 6: Convert 1 to the same denominator as 2 (2/2).
c/1 + 1/2 is equivalent to c/1 + 2/2

Step 7: Combine the fractions.
c/1 + 2/2
c/1 + 2/2 = (c + 2)/2

Therefore, the carbon concentration in a 11460-year-old bone is (c + 2)/2 parts per trillion.