looks like we can use grouping
x^3 - 5x^2 - x + 5
= x^2(x-5) - 1(x-5)
= (x-5)(x^2-1)
= (x-5)(x+1)(x-1)
Factor completely
x^3 - 5x^2 - x + 5
2 answers
Thank you!
x^3 - 5x^2 - x + 5
2 answers