Question
Factor completely
x^3 - 5x^2 - x + 5
x^3 - 5x^2 - x + 5
Answers
Reiny
looks like we can use grouping
x^3 - 5x^2 - x + 5
= x^2(x-5) - 1(x-5)
= (x-5)(x^2-1)
= (x-5)(x+1)(x-1)
x^3 - 5x^2 - x + 5
= x^2(x-5) - 1(x-5)
= (x-5)(x^2-1)
= (x-5)(x+1)(x-1)
Alyssa
Thank you!