Asked by Alyssa

Factor completely
x^3 - 5x^2 - x + 5

14 years ago

Answered by Reiny

looks like we can use grouping
x^3 - 5x^2 - x + 5
= x^2(x-5) - 1(x-5)
= (x-5)(x^2-1)
= (x-5)(x+1)(x-1)

14 years ago

Answered by Alyssa

Thank you!

14 years ago

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