Asked by John
Factor completely:
X^3n+y^3n
Do I factor it as a cube?
Can't figure it out
X^3n+y^3n
Do I factor it as a cube?
Can't figure it out
Answers
Answered by
Steve
this is the sum of two cubes:
(x^n)^3 + (y^n)^3
(x^n + y^n)(x^2n - x^n y^n + y^2n)
(x^n)^3 + (y^n)^3
(x^n + y^n)(x^2n - x^n y^n + y^2n)
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