Ask a New Question

Question

factor completely
n^4-y^4
(n^2+Y^2)(n^2-y^2)
(n^2+y^2)(n+y)(n-y)
Did I do this correctly?
Thank you
12 years ago

Answers

Jai
Yes, that's correct. :)
12 years ago
shrestha tejaswi
It is so easy, why you're confused?it is correct dude!
12 years ago

Related Questions

factor completely 1. x^3-9x^2 2. 36x^6-49x^4 Factor Completely a. 3x^8-3x^6 b. 20a^2b^2x^2-45a^2b^2y^2 Factor each completely. 10b^2-4b-6 ^means exponent Factor completely: 54+16x^3 factor completely 1) 8x^3 + 27y^3 2) u^3 + 125v^3 factor completely a^9+b^12 c^15 factor completely a^2-49 If possible, completely factor the expression. (If the polynomial is not factorable using integers,... Factor completely. 3f2+33f–78
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use