Asked by Amy
1. Simplify the expression ((5x^-2)/(4x^2))^-2
2. (x)/(x^2-81)-(9)/(81-x^2) =
3. Let (-3,3) and (-6,_2) be points in the Cartesian plane. Find the distance between the points.
2. (x)/(x^2-81)-(9)/(81-x^2) =
3. Let (-3,3) and (-6,_2) be points in the Cartesian plane. Find the distance between the points.
Answers
Answered by
Reiny
((5x^-2)/(4x^2))^-2
= (5x^-2)(4x^2)^2
= (5x^-2)(16x^4)
= 80x^2
2. Do you realize that 81 - x^2 = -(x^2 - 81)
so (x)/(x^2-81)-(9)/(81-x^2)
= x/(x^2 - 81) + 9/(x^2 - 81)
= (x-9)/((x+9)(x-9))
= 1/(x+9) , x ≠ 9
= (5x^-2)(4x^2)^2
= (5x^-2)(16x^4)
= 80x^2
2. Do you realize that 81 - x^2 = -(x^2 - 81)
so (x)/(x^2-81)-(9)/(81-x^2)
= x/(x^2 - 81) + 9/(x^2 - 81)
= (x-9)/((x+9)(x-9))
= 1/(x+9) , x ≠ 9
Answered by
Reiny
for #3
you should have a formula for the distance between 2 points.
you should have a formula for the distance between 2 points.
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