Asked by boo
1.Simplify the expression: cos^2 theta- cos^4 theta/ tan theta
Answers
Answered by
Tammy
assuming you meant:
(cos^2 θ- cos^4 θ)/ tan θ
= cos^2 θ(1 - cos^2 θ)/tan θ
= cos^2 θ sin^2 θ / (sinθ/cosθ)
= cos^2 θ sin^2 θ cosθ/sinθ
= cos^2 θ sinθ
or
= (1 - sin^2 θ) sinθ
= sinθ - sin^2 θ
(cos^2 θ- cos^4 θ)/ tan θ
= cos^2 θ(1 - cos^2 θ)/tan θ
= cos^2 θ sin^2 θ / (sinθ/cosθ)
= cos^2 θ sin^2 θ cosθ/sinθ
= cos^2 θ sinθ
or
= (1 - sin^2 θ) sinθ
= sinθ - sin^2 θ
Answered by
oobleck
Hmmm.
= cos^2 θ sin^2 θ cosθ/sinθ
= cos^3 θ sinθ
or
cos^2θ sinθ cosθ
(1+cos2θ)/2 * 1/2 sin2θ
= (1 + cos2θ)sin2θ/4
or
sin2θ/4 + sin4θ/8
= cos^2 θ sin^2 θ cosθ/sinθ
= cos^3 θ sinθ
or
cos^2θ sinθ cosθ
(1+cos2θ)/2 * 1/2 sin2θ
= (1 + cos2θ)sin2θ/4
or
sin2θ/4 + sin4θ/8
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