sin2x-cosx (0<=x<=180)

(sinx-cosx)^2=sin2x

for sin2x+cosx=0, use double-angle or half-angle formula to simplify the equation and then find all...

sin2x+cosx=0 , [-180,180) = 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2...

1+sin2x/sin2x=1+1/2(secx)(cscx)

(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x

Prov that 1-sin2X/sinX-cosX=sinX-cosX

Sin2x+cosx

Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx

If Y=sin2x/cosx than dy/dx is

1-sin2x/cosx=tan(π/4-x)

Question