Asked by Anonymous

A students on a balcony uses a slingshot to shoots rock straight up

at 29.4 m/s. If the rock takes 8.0 s seconds to hit the ground below the balcony, how high is the balcony above the ground?

Answers

Answered by Henry
The velocity 0f the rock is zero at its' max. height:

Vf = Vo + gt = 0,
29.4 - 9.8t = 0,
-9.8t = -29.4,
t = -29.4 / -9.8 = 3s to reach max height
Time in flight = 8s.
Fall time = 8 - 3 = 5s,

d = 0*5 + 0.5*9.8*5^2,
d = 0 + 122.5 = 122.5m to gnd.

h = 122.5 - 44.1 = 78.4m.





























= 4.9*3^2,
d = 88.2 - 44.1 = 44.1m up.

Answered by Henry
Oops!!

d (up) = Vo*t + 0.5*gt^2,
d (up) = 29.4*3 + 0.5*(-9.8)3^2,
d (up) = 88.2 - 44.1 = 44.1m.
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