Asked by anonymous
A ball is thrown off a balcony (40 m high) and has an initial velocity of 18 m/s horizontally. (a) Determine the position of the ball at t = 4.0 s. (b) Determine the position after 4.0s?
Answers
Answered by
bobpursley
vertical position:
hf=40-9.8/2 * t^2
hf=40-4.9*16 Hmmm, it below ground level? or..the problem is flawed.
hf=40-9.8/2 * t^2
hf=40-4.9*16 Hmmm, it below ground level? or..the problem is flawed.
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