Asked by Maria
A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?
Answers
Answered by
DrBob222
moles = grams/molar mass
Solve for moles.
molality = moles/kg solvent
Solve for molality
delta T = Kf*molality
Solve for delta T, then for the freezing point knowing the normal freezing point is zero C.
Solve for moles.
molality = moles/kg solvent
Solve for molality
delta T = Kf*molality
Solve for delta T, then for the freezing point knowing the normal freezing point is zero C.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.