Asked by Helen

Complete the table below:
For each of the following sets pick the compound with the highest conductivity in a 1 M aqueous solution.
(Enter the number at the top of the column containing the correct answer.)
1 2 3 Answers
a HCl HC2H3O2 H2PO4–
b KNO3 Ca(NO3)2 HNO3
c CH3OH NaOH HOC6H5
d Li2CO3 Na2CO3 K2CO3
e NaCl MgCl2 AlCl3

Answers

Answered by bobpursley
Look for the compound which in a dilute solution has the most ions. for instance, in b

KNO3 is completed ionized,2 ions per molecule
Ca(NO3)2, three ions, but one of them carries two charges, so in fact one moleucle can break up to carry 5 net charges.
HNO3, 100 precent dissoacated, but two ions per molecule.
Answer: circle calcium nitrate.
Answered by Chris
I still don't understand. Can someone help, and elaborate more?
Answered by robin
for B Ca(NO3)2 is NOT the right answer. i got it wrong.
Answered by Anonymous
lol UCI students
Answered by Anonymous
Yes, UCI students. We haven't learned this in lecture.
Answered by Anonymous
I know that HCl is one of the correct choices
Answered by anonymous
hey UCI!

a. HCl
b. HNO3
c. NaOh
d. K2CO3, also in the lab we did. it all depends on the cation (k, li, and na) which one has the highest mass
e. AlCl3 (that was in the lab we did.)
Answered by Anonymous
you are my hero.
Answered by Anonymous
its wrong...^^^^^^^ is wrong!! :(
Answered by Anonymous
never mind!!!! its right lol! dude u guys.. my chem teacher didn't go over this neither did the TA.....
Answered by Anonymous
You are seriously my hero.
Answered by j
you are amazing!
Answered by Kaden
UCI FTW. Haha webworks has NOTHING to do with lecture. They don't correspond, it suuuucckkks.
Answered by Anonymous
omgggg yay..i thought i was never going to figure this out....i freaking HATE webworks
Answered by SJ
Do we really need to know all of this for the lecture AND lab??

Are these going to be on the test?
Answered by anonymous
chem lab uci 2012! suffering with this a year later =/
Answered by Alex
YEA UCI chem lab where 2units > 4 units
Answered by Awesome
Thanks man.
Answered by jay
Thank gosh... herooooo.... I have no clue with these webwork question

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