Question

find the molarity of bezene given the denisty of .8989 g/l and the boiling temp is 80.2 C and Kb= 2.53C kg/mol

Answer 1

You need to add the other details of the problem.

Answer 2

umm its says 5g of n2h4oc was dissolved in 100 gr of benzene

Answer 3

and the boiling temp is 82.3 C the 80.2 is for pure benzene

Answer 4

That helps. Will you check and tell me if you want the molality or the molarity?

Answer 5

Molarity

Answer 6

First note: Lower case letters won't get it in chemistry, unless they really ARE lower case. n2h4oc doesn't mean a thing to me. I will refer to it as the compound. Do you have a name for the n2h4oc?
Second note:I still don't understand the problem. The molarity of the compound can be determined without using the boiling point data. The molarity of the benzene (which I assume to be the solvent) makes no sense (unless the compound is the solvent).

Answer 7

N2H4OC its the solid being dissolved that's in the problem

You may not need the boiling point data i just figure i write it because it was in the problem

Answer 8

One more question? The solute USUALLY is the solid and the solvent USUALLY is the liquid. You want the molarity of the solid or the molarity of the benzene?

Answer 9

of benzene

Answer 10

I will assume when you say molarity of the benzene that you mean the molarity of the solution (which is benzene with the solution dissolved in it).
mols N2H4CO = grams/molar mass = 0.08333
mol.
molality = moles/kg solvent = 0.08333/0.1 kg solvent = 0.8333 m

Not you convert 0.8333 m to M.
Take 1 kg of the solution (which has a density of 0.8989 g/mL (surely it isn't g/L as in your initial post). That contains 0.8333*60 = 50 g N2H4CO. Add that to the 1000 g benzene and we have 50 g N2H4CO in 1050 g of the solution with a density of 0.8989 g/mL.
What is the volume of the solution?
volume = mass/density = 1050/0.8989 = 1,168 mL or 1.168 L. Then M = moles/L = ??. (0.8333/1.168). Check my work. This has been a confusing problem to me.

Answer 11

your telling me thank you

Answer 12

Hawaii gets 1.168*10^3 cm of rainfalll per year. Express this quantity in meters. Show work.

Answer 13

hey bot

Answer 14

Hello! How can I assist you today?

Answer 15

−68 − 21
Responses
A −47−47
B −89−89
C 8989
D 47

Answer 16

The answer would be

-68 - 21 = -89

Therefore, the answer choice is (B) -89.

Answer 17

and −75 − (−75)
Responses
A 140140
B 150150
C 00
D −150

Answer 18

The answer would be

-75 - (-75) = -75 + 75 = 0

Therefore, the answer choice is (C) 0.

Answer 19

thanks byeeeee

Answer 20

You're welcome. Goodbye!