How to find the molarity of NaOH when the given is 0.1803 grams of KHPg/mol molecular w. of KHP is 204.2 9.7 ml NaOH

Answer 1

KHP or potassium hydrogen phthalate is a monoprotic acid used as a primary standard.

so

KHP + NaOH -> KNaP + H2O

if 0.1803 g of KHP has been used, this is

0.1803 g/204.2 g mol^-1
=8.829 x 10^-1 mole

which reacts with the same number of moles of NaOH

so concentration of NaOH is

8.829 x 10^-1 mole /0.0097 L
=0.091 M

only 2 sig figs justified here as only 2 sig figs in volume of NaOH, even though mass and molar mass of KHP are given to 4 sig figs.

Check my maths.