Asked by Jodie
Solve each system by the substitution method.
x+3y=2
-x+y=1
x+3y=2
-x+y=1
Answers
Answered by
Jen
x+3y=2
-x+y=1 so y=x+1, substitute that into the 1st
x+3(x+1)=2
x+3x+3=2
4x+3=2
4x=-1
x=-1/4
Substitute that into either of the original equations to solve for y.
-x+y=1 so y=x+1, substitute that into the 1st
x+3(x+1)=2
x+3x+3=2
4x+3=2
4x=-1
x=-1/4
Substitute that into either of the original equations to solve for y.
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