Asked by Please help
How do you solve this by substitution?
x=6y+2
3x-18y=4
This is the answer I get:
3(6y+2)-18y=4
18y+6-18y=4
18y+1818y+6-18y+18y=4
36y=10
36 36
Y=5/18
3x-18(5/18) =4
3x-5+5= 4+5
3x= 9
3 3
X=3
(3, 5/18)
x=6y+2
3x-18y=4
This is the answer I get:
3(6y+2)-18y=4
18y+6-18y=4
18y+1818y+6-18y+18y=4
36y=10
36 36
Y=5/18
3x-18(5/18) =4
3x-5+5= 4+5
3x= 9
3 3
X=3
(3, 5/18)
Answers
Answered by
Steve
If you rearrange things a bit, you get
x - 6y = 2
3x - 18y = 4
which is the same as
x - 6y = 2
x - 6y = 4/3
The lines are parallel, so there is no intersection, and no solution to the equations.
Your answer fits the 2nd equation, but not the first.
x - 6y = 2
3x - 18y = 4
which is the same as
x - 6y = 2
x - 6y = 4/3
The lines are parallel, so there is no intersection, and no solution to the equations.
Your answer fits the 2nd equation, but not the first.
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