A coin is tossed five times. Find the probability of getting four tails.

I realize that getting four tails is the exact same thing as getting only one heads, but how would you figure out this problem using probability rules? Thanks for your time, I appreciate it :]

2 answers

so want all arrangements of
TTTTH
that is, TTTTH, TTTHT, TTHTT, THTTT, HTTTT

The prob of each one = (1/2)(1/2)(1/2)(1/2)(1/2) = 1/32

so prob of your event = 5(1/32) = 5/32
Ohhh I get it now! Thanks so much!