Asked by Eggo
Coin A is tossed three times and coin B is tossed two times. What is the probability that more heads are tossed using coin A than coin B?
THE ANSWER IS NOT 7/16
THE ANSWER IS NOT 7/16
Answers
Answered by
Steve
Just counting the heads tossed,
P(3,2) = 1/8 * 1/4
P(3,1) = 1/8 * 1/2
P(3,0) = 1/8 * 1/4
P(2,1) = 3/8 * 1/2
P(2,0) = 3/8 * 1/4
P(1,0) = 3/8 * 1/4
P(A>B) = ∑P(A,B) = 1/2
P(3,2) = 1/8 * 1/4
P(3,1) = 1/8 * 1/2
P(3,0) = 1/8 * 1/4
P(2,1) = 3/8 * 1/2
P(2,0) = 3/8 * 1/4
P(1,0) = 3/8 * 1/4
P(A>B) = ∑P(A,B) = 1/2
Answered by
Eggo
That is correct. Thanks.
Answered by
Ronald Kunda Chitungulu
Simulate the supply for 20 days using the random numbers below in order to calculate the expected average from 6,68,59,75,96,68,71,71,69,31,28,99,76,38,53,10,78,38,84,65
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.