A coin is tossed 8 times. The probability of getting a head on any one toss is 0.5. To the nearest thousandth, find the probability of getting

Question

4 heads.
P(4 heads)=we want 4 of 8 heads
8 nCr 4 (1/2)^4(1-1/2)^8-4
70(1/16)*(1/2)^4
I am lost from here

Answer 1

I don't understand why you stopped in the middle of your arithmetic,
after all you just found (1/2)^4 = 1/16
What was different in the (1/2)^4 further along your answer ??

8C4 (1/2)^4(1-1/2)^8-4
= 70(1/16)(1/16) = 70/256
= 35/128