Asked by stephen
A baseball player hits a line drive to center field. As he rounds second base, he heads directly for third, running at 20 ft/sec. How fast is the distance from the rnner to home plate changing when he is halfway to third base?
Answers
Answered by
Damon
aargh, did this yesterday, going to look
Answered by
bobpursley
http://www.jiskha.com/search/index.cgi?query=A+baseball+player+hits+a+line+drive+to+center+field.+As+he+rounds+second+base%2C+he+heads+directly+for+third%2C+running+at+20+ft%2Fsec.+How+fast+is+the+distance+from+the+rnner+to+home+plate+changing+when+he+is+halfway+to+third+base%3F+
Answered by
Damon
h^2 = 90^2 + x^2
h is hypotenuse
x is distance from third
where x = (45-20t) so dx/dt = -20
2 h dh/dt = 2 x dx/dt
dh/dt = (x/h) (-20)
at t = 0, x = 45 and h = 100.6
so
dh/dt = -8.94
h is hypotenuse
x is distance from third
where x = (45-20t) so dx/dt = -20
2 h dh/dt = 2 x dx/dt
dh/dt = (x/h) (-20)
at t = 0, x = 45 and h = 100.6
so
dh/dt = -8.94
Answered by
Damon
http://www.jiskha.com/display.cgi?id=1293827209
Answered by
Damon
x^2 = (45-20*t)^2 + 90^2
2 x dx/dt = 2 *(45-20t) (-20)
at x=sqrt(45^2+90^2) when t = 0
2 (100.6) dx/dt = 90*-20
dx/dt = -8.94 ft/s
2 x dx/dt = 2 *(45-20t) (-20)
at x=sqrt(45^2+90^2) when t = 0
2 (100.6) dx/dt = 90*-20
dx/dt = -8.94 ft/s
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