Question
A car moves from a point located 26.0 m from the origin and at an angle of 35.0° from the x-axis to a point located 56.0 m from the origin and at an angle of 60.0° from the x-axis in 2.50 s. What is the magnitude of the average velocity of the car?
Answers
Henry
X = hor. = 26cos35 + 56cos60,
X = 21.3 + 28 = 49.3 m.
Y = ver. = 26sin35 + 56sin60,
Y= 14.9 + 48.5 = 63.4 m.
d^2 = X^2 + Y^2,
d^2 = (49.3)^2 + (63.4)^2,
d^2 = 2430.5 + 4019.6,
d^2 = 6450.1,
d = 80.3 m.
Vavg = d / t = 80.3 / 2.5 = 32.1 m/s.
X = 21.3 + 28 = 49.3 m.
Y = ver. = 26sin35 + 56sin60,
Y= 14.9 + 48.5 = 63.4 m.
d^2 = X^2 + Y^2,
d^2 = (49.3)^2 + (63.4)^2,
d^2 = 2430.5 + 4019.6,
d^2 = 6450.1,
d = 80.3 m.
Vavg = d / t = 80.3 / 2.5 = 32.1 m/s.