Asked by Anonymous
1. A boy moves from a point X and walks 285m to Y on a bearing of 078° . He then moves due south to a point Z, which is 307m from X. Calculate:
a) the bearing of X from Z
b) the distance between YZ
a) the bearing of X from Z
b) the distance between YZ
Answers
Answered by
oobleck
Using the law of cosines,
307^2 = 285^2 + YZ^2 - 2*285*YZ*cos78°
YZ = 187.84
In triangle XYZ, find angle Z using the law of sines:
sinZ/285 = sin78°/307
Z = 65°
So, the bearing of X from Z is 360-65 = 295°
307^2 = 285^2 + YZ^2 - 2*285*YZ*cos78°
YZ = 187.84
In triangle XYZ, find angle Z using the law of sines:
sinZ/285 = sin78°/307
Z = 65°
So, the bearing of X from Z is 360-65 = 295°
Answered by
hhshhj
C0rrect
Answered by
hhshhj
Correct
Answered by
Kaz
Nice one
Answered by
Endurance Wilson
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