Asked by Sarah
The Henry's Law constant for O2 in water is 1.28 x 10 ^ -3 M/atm. How many grams of O2 will dissolve in a 12 L fish tank on a day when atm is .977 and air is 18% O2?
Show steps
Show steps
Answers
Answered by
DrBob222
I looked on the net at this site to see the formula you must be using for Henry's Law (many different versions in use). You can read more about it here.
http://en.wikipedia.org/wiki/Henry%27s_law
You must be using c = pk; therefore,
c = (0.18*0.977)*1.28E-3
c = 2.25E-4 M. Convert that to grams (g = moles x molar mass) for the mass O2 in 1L, convert that to 12L.
http://en.wikipedia.org/wiki/Henry%27s_law
You must be using c = pk; therefore,
c = (0.18*0.977)*1.28E-3
c = 2.25E-4 M. Convert that to grams (g = moles x molar mass) for the mass O2 in 1L, convert that to 12L.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.