A violin has an open string length (bridge to nut) of L=32.7 cm. At what distance x from the bridge does a violinist have to place his finger on the fingerboard to play a C (523.3 Hz) on the A string (fundamental frequency 440 Hz)?

Answer 1

fundamental frequency (ff) = 440 Hz
frequency at C (fc)= 523.3 Hz
L = 32.7 cm
L(C) = ?
x(C) = ?

L (C) = L * ff/fc
L (C) = 27.50 cm

x (C) = L - L(C) = 5.20 cm

Finger has to be placed at 5.20 cm from the end.