Asked by Vinicius
The E string of a violin has a linear density of 0.5 g / m and is subjected to a
80N of tension, tuned for a frequency = 660 Hz
a) What is the length of the rope?
80N of tension, tuned for a frequency = 660 Hz
a) What is the length of the rope?
Answers
Answered by
bobpursley
Oscillations? wavelength=speedsound/freeq
so what is the speed of sound on the string? The speed of propagation of a wave in a string (v) is proportional to the square root of the tension of the string (F) (discovered by Vincenzo Galilei in the late 1500s) and inversely proportional to the square root of the linear density (\mu) of the string:
speed= sqrt(tension/mu) remember mu needs to be in kg/meter
so now you have speed, calculate wavelength, then the length of the rope is one half wavelength...
so what is the speed of sound on the string? The speed of propagation of a wave in a string (v) is proportional to the square root of the tension of the string (F) (discovered by Vincenzo Galilei in the late 1500s) and inversely proportional to the square root of the linear density (\mu) of the string:
speed= sqrt(tension/mu) remember mu needs to be in kg/meter
so now you have speed, calculate wavelength, then the length of the rope is one half wavelength...
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