Question
alexander had some nickles in his bank. he added 3 dimes to the bank and then he had 85 cents.how many nickles did he have left? write an equation and work backward to solve.
Answers
Katie
.05(x)+ .10(3)=.85
.05x+ .3=.85
-.3 -.3
.05x=.55
/.05 /.05
x=11
.05x+ .3=.85
-.3 -.3
.05x=.55
/.05 /.05
x=11