"Dryness fraction" is the fraction of the original H2O mixture that is water vapor. The rest is liquid. Assuming that the throttling process does not alter that ratio, it would appear to be 1.8/(1.8 + 0.16) = 0.92
But I could be wrong
A combined seperating and throttling calorimeter was used to determined the dryness fraction of steam flowing through a steam main at a pressure of 900kPa. The pressure and temperature after throttling were 100kPa and 110C respectively. The mass of water collected in the seperator was 0.16kg and the mass of steam condensate collected from the condenser was 1.8kg. determine the dryness fraction of the steam in the steam main.
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1 answer