If we combined 18.00 g of KOH and 18.00 g of H2SO4 , and they reacted according to the equation below, how many moles of K2SO4 should be made if all of the KOH is used?

Question

If we combined 18.00 g of KOH  and 18.00 g of H2SO4 , and they reacted according to the equation below, how many moles of K2SO4 should be made if all of the KOH is used?
 2 KOH  +  H2SO4 =  2 H2O  +  K2SO4

DrBob222 · Answer

mols KOH = g/molar mass = 18.00/56.1 = 0.321 0.321 mols KOH x ( 1 mol K2SO4/2 mols KOH) = 0.321/2 = ? mols K2SO4. This assumes KOH is the limiting reagent.