Question
If we combined 18.00 g of KOH and 18.00 g of H2SO4 , and they reacted according to the equation below, how many moles of K2SO4 should be made if all of the KOH is used?
2 KOH + H2SO4 = 2 H2O + K2SO4
2 KOH + H2SO4 = 2 H2O + K2SO4
Answers
DrBob222
mols KOH = g/molar mass = 18.00/56.1 = 0.321
0.321 mols KOH x ( 1 mol K2SO4/2 mols KOH) = 0.321/2 = ? mols K2SO4. This assumes KOH is the limiting reagent.
0.321 mols KOH x ( 1 mol K2SO4/2 mols KOH) = 0.321/2 = ? mols K2SO4. This assumes KOH is the limiting reagent.