Asked by Matthew
A rectangle's length is 8 cm more than three times it's width. If the perimeter is 128 cm, find the length and width. What is the equation for this?
Answers
Answered by
drwls
You need to sove two simultaneous equations.
L = length W = width
L = 3W + 8
2(L + W) = 128
Substitute 3W +8 for L in the last equation.
2[(3W+8)+ 2W] = 128
8W + 16 = 128
8W = 112
W = ?
L = 3W +8 = ?
L = length W = width
L = 3W + 8
2(L + W) = 128
Substitute 3W +8 for L in the last equation.
2[(3W+8)+ 2W] = 128
8W + 16 = 128
8W = 112
W = ?
L = 3W +8 = ?
Answered by
DrBob222
L + L + W + W = 128
L - 8 = 3W
================
Two equations. Two unknowns. Solve simultaneously.
L - 8 = 3W
================
Two equations. Two unknowns. Solve simultaneously.
Answered by
hello
3 and 8
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