Asked by sandhu

A block starts with a speed of 18.0 m/s and slides for a distance of 2.2 m down a 40° ramp (ìk = 0.43). What is its final speed? (m/s)
Answered by drwls
Final KE = PE loss - (work done against friction)
(1/2)M V^2 = M g L sin40 - M g L cos40*0.43
L = 2.2 m. Cancel out the M's and solve for V^2.
Answered by sandhu
What about the initial speed of 18.0 m/s when it starts?
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